aexlmx @ 2024-11-25 18:47:52
case 6:
b=sqrt(6*6+9*9);
printf("%f",b);
break;
case 8:
c=2*pi*5.;s=pi*25.;v=4*pi*125./3;
printf("%f\n%f\n%f",c,s,v);
break;
case 11:
float d=100/3.0;
printf("%f",d);
break;
by JYS005 @ 2024-12-01 10:24:19
@aexlmx@aexlmx P2433的题意是认你将全部问题都列出来,之后用分支或者case的开关语句选择一个问题作为回答