wh_duyuhao @ 2024-11-27 19:28:46
#include<iostream>
using namespace std;
int main(){
int k;
cin>>k;
int n=0,i=0;
double ans=0;
while(1){
ans+=1.0/i;
n++;
if(ans>k) break;
i++;
}
cout<<n;
return 0;
}
????????????????????????
by PengRuiXuan @ 2024-11-27 19:32:18
#include <bits/stdc++.h>
using namespace std;
int main() {
int n = 1;
double s = 1, k;
cin >> k;
while (s <= k) {
n++;
s += 1.00 / n;
}
cout << n << endl;
return 0;
}
by wh_duyuhao @ 2024-11-27 19:32:33
求回!!!!!!!
by wh_duyuhao @ 2024-11-27 19:33:11
666,又是答案。
by wh_duyuhao @ 2024-11-27 19:33:47
求大佬帮我点明错误!
by PengRuiXuan @ 2024-11-27 19:34:57
@wh_duyuhao
OK等一下。
by wangjingxi_ @ 2024-11-27 19:37:48
#include<iostream>
using namespace std;
int main()
{
long double n=0,k,sum=0;
cin>>k;
while(sum<=k)
{
sum+=(1.0/(n+1));
n++;
}
cout<<n;
return 0;
}
对了一下,好像也没问题,你把这个代码交一下试试。
by PengRuiXuan @ 2024-11-27 19:39:03
把n和ans的初始值改成1可以过样例,但是只能过一个测试点。
by wh_duyuhao @ 2024-11-27 19:40:11
我知道,因为我认为这个发出来的代码应该全对!
by wh_duyuhao @ 2024-11-27 19:41:40
@wangjingxi_ ???全对? 咱们两个代码改一下是一样的啊!
by wh_duyuhao @ 2024-11-27 19:43:51
我的“i”设置的值是“0”!