PLDIS @ 2024-11-29 22:55:20
RT,这个代码输出的 SCC 缩点后总是一个合法的拓扑序。(参考题目)
bug or feature
vector<int> gv[500001], scc[500001];
stack<int> st;
int dfn[500001], low[500001], ins[500001], cnt = 0, tot = 0, n, m;
inline void add_edge(int u, int v){
gv[u].push_back(v);
}
void Tarjan(int u){
dfn[u] = low[u] = ++tot;
st.push(u); ins[u] = 1;
for(auto v : gv[u]){
if(dfn[v] && ins[v])
low[u] = min(low[u], dfn[v]);
else if(!dfn[v]){
Tarjan(v);
low[u] = min(low[u], low[v]);
}
}
if(low[u] == dfn[u]){
cnt++; int x = st.top();
do{
scc[cnt].push_back(x = st.top());
ins[st.top()] = 0;
st.pop();
}while(x != u);
}
}
void init_vars(){
// type your initiating code...
}
void solve(int testcase, ...){
init_vars();
cin >> n >> m;
for(int i = 1; i <= m; i++){
int u, v; cin >> u >> v;
u++, v++;
add_edge(u, v);
}
for(int i = 1; i <= n; i++){
if(!dfn[i]) Tarjan(i);
}
cout << cnt << endl;
for(int i = cnt; i >= 1; i--){
cout << scc[i].size() << " ";
for(auto x : scc[i])
cout << x - 1 << " ";
cout << endl;
}
}
by cff_0102 @ 2024-11-29 23:12:40
@PLDIS OIWiki 有证明的
by WaterSun @ 2024-11-29 23:12:53
@PLDIS link