这个怎么就20分，泪

ydwide @ 2024-12-04 21:17:31

#include<stdio.h>
int main(){
    int s,v;
    scanf("%d%d",&s,&v);
    int m;
    if(s%v==0){
        m=(int)(s/v)+10;
    }else{
        m=(int)(s/v)+1+10;
    }
    int h;
    if(m>8*60){
        if(m%60==0){
            h=(m-480)/60;
        }else{
            h=(m-480)/60+1;
        }
        printf("%d:%d",24-h,60-m);
    }else{
        if(m%60==0){
            h=m/60;
        }else{
            h=m/60+1;
        }
        printf("0%d:%d",8-h,60-m);
    }
    return 0;
}

by pjh0625 @ 2024-12-04 21:27:40

@ydwide

#include<bits/stdc++.h>
using namespace std;
double s,v,m;
int n,a,t,b;
int main()
{
    cin>>s>>v;
    n=8*60+24*60;
    t=ceil(s/v)+10;//ceil()
    n=n-t;
    if(n>=24*60) n-=24*60;
    b=n%60;
    a=n/60;
    if(a<10)
    {
        if(b<10) cout<<"0"<<a<<":0"<<b;
        else cout<<"0"<<a<<":"<<b;
    }
    else
    {
        if(b<10) cout<<a<<":0"<<b;
        else cout<<a<<":"<<b;
    }
    return 0;
}

by lipeizheng @ 2024-12-04 21:50:54

太复杂了，其实把时间用分钟表示，然后用double 定义 t 和 s 求出用时（注意向上取整）在与时间相减，若用时大于470分钟，再把时间加上24*60，之后补0输出即可。 AC记录https://www.luogu.com.cn/record/192845786

by woshilaohu @ 2024-12-08 22:47:39

@[pjh0625](luogu://user/1339889@pjh0625逆天哥们要的就是c你发个c++

by pjh0625 @ 2024-12-08 22:58:57

@woshilaohu

#include <stdio.h>
#include <math.h>

int main() {
    double s, v;
    int n, a, t, b;

    scanf("%lf %lf", &s, &v);
    n = 8 * 60 + 24 * 60;
    t = ceil(s / v) + 10; 
    n = n - t;

    if (n >= 24 * 60) n -= 24 * 60;
    b = n % 60;
    a = n / 60;

    if (a < 10) {
        if (b < 10) {
            printf("0%d:0%d\n", a, b);
        } else {
            printf("0%d:%d\n", a, b);
        }
    } else {
        if (b < 10) {
            printf("%d:0%d\n", a, b);
        } else {
            printf("%d:%d\n", a, b);
        }
    }

    return 0;
}