Laugh_at_the_sky @ 2024-12-09 20:56:48
#include <iostream>
using namespace std;
char buf[1 << 20], *_now = buf, *_end = buf;
#define getchar() (_now == _end && (_end = (_now = buf) + fread(buf, 1, 1 << 20, stdin), _now == _end) ? EOF : *_now++)
int input() {
int x = 0, f = 1;
char ch = getchar();
while (isdigit(ch) ^ 1) {
if (ch == '-') f = -1;
ch = getchar();
}
while (isdigit(ch)) {
x = x * 10 + ch - '0';
ch = getchar();
}
return x * f;
}
void solve() {
int A = input(), B = input();
cout << A + B << "\n";
}
int main() { solve(); }by ttq012 @ 2024-12-09 21:26:07
@guoj（如果我没记错的话），好像是合法为任意非零数，不合法为 0
也就是说如果这么定义 isdigit 函数也是合法的
int my_isdigit(char x) {
if (x >= '0' && x <= '9') return rand() + 1;
return 0;
}by ttq012 @ 2024-12-09 21:26:24
（顺带一提 isdigit 函数返回值是 int）
by guoj @ 2024-12-09 21:30:57
@ttq012 好像确实有
by luoguplay @ 2025-01-04 16:01:37
#include <iostream>
using namespace std;
int main()
{
int a, b;
cin >> a >> b;
cout << a + b;
}