求解惑

A2567196969 @ 2024-12-12 12:25:15

by KarmaticEnding @ 2024-12-12 12:25:56

@A2567196969

你可以看：数据范围

by banglee @ 2024-12-12 12:26:10

@A2567196969 给代码

by KarmaticEnding @ 2024-12-12 12:27:03

@A2567196969

要是没懂，测一下这组样例

输入：

100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
10

输出：

10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

by LionBlaze @ 2024-12-12 12:43:47

@A2567196969 Talk is cheap. Show me your code.

by wuyouawa @ 2024-12-12 12:47:13

@LionBlaze 他的提交记录里找到了：这里

by A2567196969 @ 2024-12-13 23:42:40

@banglee

 #include<string.h>
 #include<stdio.h>
int main()
{
    char str1[5001] = { 0 };
    int b;
    gets(str1);
    scanf("%d", &b);
    int len1 = strlen(str1);
    int arr1[20001] = { 0 };
    int num1 = 0;
    for (int i = 0; i < len1; i++)
    {
        num1 = num1 * 10 + (str1[i] - '0');
        arr1[i] = num1 / b;
        num1 = num1 % b;
    }
    int num2 = 0;
    for (int i = 0; i < len1; i++)
    {if (arr1[i] != 0)num2 = 1;
        if (num2 == 1)printf("%d", arr1[i]);
    }
    if (num2 == 0)printf("0");

}@KarmaticEnding@banglee