runtime error！超绝白痴看不出错在哪里

FC995 @ 2024-12-24 10:47:58

#include <stdio.h>
#include <math.h>

int main(){
    int n;
    scanf("%d", &n);
    float a[n];
    float sum=0.00;
    float difference=0.00;

if(n>2 && n<=300){
    for(int i=0;i<n;i++){
        scanf("%f", &a[i]);
    }//写一个 循环输入

    float max=a[0];
    float min=a[0];
    for(int i=0;i<n;i++){
        max=(a[i]>=max)?a[i]:max;
        min=(a[i]<=min)?a[i]:min;
        sum=sum+a[i];
    }//找出最大值和最小值

    float current_sum=sum-max-min;
//去除最大值和最小值
    float average=current_sum/(n-2);
//算出平均值
    //printf("%.2f", average);

    for(int i=0;i<n;i++){
        if(a[i]!=max&&a[i]!=min){
            float temp=difference;
//想用temp储存上一次的difference的值 便于比较
            difference=abs(a[i]-average);
//在有效数字内 算出他们和平均值差值

        if(temp>difference){
            difference=temp;
        }else if(temp<difference){
            return 1;
        }else{
            difference=0.00;
        }
//新的difference和上一个的作比较
        }
        printf("%.2f   %.2f",average, difference);
//按照题目要求输出结果
    }
}

return 0;
}

by PengRuiXuan @ 2024-12-24 10:50:16

#include<bits/stdc++.h>
using namespace std;
int main(){
    int n,x,y;
    double a[301],min,max,sum,ave,diff=0;
    cin>>n;
    cin>>a[0];
    min=a[0];
    max=a[0];
    sum=a[0];
    for(int i=1;i<n;i++){
        cin>>a[i];
        if(a[i]>=max){
            max=a[i];
            x=i;
            }
        else if(a[i]<=min){
            min=a[i]; 
            y=i;
        }
        sum=sum+a[i];
    }
    ave=(sum-max-min)/(n-2);
    for(int i=0;i<n;i++){
        if(i!=x&&i!=y)
            if(fabs(a[i]-ave)>diff)
                diff=fabs(a[i]-ave);
    }
    cout<<setprecision(2)<<fixed<<ave<<" ";
    cout<<setprecision(2)<<fixed<<diff;
    return 0;
}

by Diary_Of_Young @ 2024-12-25 17:02:57

#include<bits/stdc++.h>
using namespace std;
double a[101001] , sum , cnt;
int n;
int main()
{
    cin >> n;

    for(int i = 1; i <= n; i ++) cin >> a[i] ;
    sort(a + 1 , a + n + 1);
    for(int i = 2 ; i < n ; i ++) sum += a[i];
    sum = 1.0 * sum / (n - 2);
    for(int i = 2 ; i < n ; i ++) cnt = max(cnt , fabs(sum - 1.0 * a[i]));
    printf("%.2lf %.2lf " , sum , cnt);
    return 0;
}