求助,样例对,80分

P5735 【深基7.例1】距离函数

ztse9172 @ 2024-12-26 21:12:37

#include<bits/stdc++.h>
using namespace std;
double d(double x1, double y1, double x2, double y2)
{
    return sqrt(abs((x1 - x2) * (x1 - x2)) + abs((y1 - y2) * (y1 - y2)));
}
int main(){
    int x1,y1,x2,y2,x3,y3;
    cin>>x1>>y1>>x2>>y2>>x3>>y3;

    double d1 = d(x1, y1, x2, y2) ;
    double d2 =d(x2,y2,x3,y3);
    double d3=d(x1,y1,x3,y3);
    double c = d1 + d2 + d3;
    cout<<fixed<<setprecision(2)<<c;    
}

by LionBlaze @ 2024-12-26 21:16:36

@ztse9172 坐标值是实数

验证码 CP32 寄


by a11223344 @ 2024-12-26 21:16:39

输入的坐标是实数,所以x1,y1,x2,y2,x3,y3应定义为double类型而不是int


by ztse9172 @ 2024-12-27 17:45:19

@LionBlaze@LionBlaze@a11223344 谢谢


|