TripFriend1130 @ 2025-01-04 15:56:56
自己测试过（没用样例），1*2是可以算的，但交上去就是听取WA声一片。。。\ 代码：
#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstring>
using namespace std;
class BigNum{
public:
int n;
int d[4000005];
BigNum()
{
n = 0;
memset(d,0,sizeof(d));
}
void read()
{
char s[2005];
scanf("%s",s);
n = strlen(s);
for(int i = 0;i<n;i++)
{
d[i] = s[n-i-1]-'0';
}
}
BigNum operator*(const BigNum &b)
{
BigNum c;
for(int i = 0;i<n;i++)
{
int num = i;
for(int j = 0;j<b.n;j++)
{
c.d[i+j] += d[i]*b.d[j];
if(c.d[i+j]>9)
{
c.d[i+j+1] = c.d[i+j]/10;
c.d[i+j]%=10;
}
num++;
}
if(c.d[b.n+i+1])
{
num++;
}
c.n += num-c.n;
}
return c;
}
};
int main()
{
BigNum a,b;
a.read();
b.read();
BigNum c = a*b;
for(int i = c.n-1;i>=0;i--)
{
cout << c.d[i];
}
return 0;
}by Endless_Freedom @ 2025-01-04 17:06:09
@TripFriend1130 AI代码能对？
by TripFriend1130 @ 2025-01-04 17:08:54
@Endless_Freedom真不是AI写的，上课跟着老师敲得
by supermzc @ 2025-01-04 17:36:30
#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstring>
using namespace std;
class BigNum{
public:
int n;
int d[4000005];
BigNum()
{
n = 0;
memset(d,0,sizeof(d));
}
void read()
{
char s[2005];
scanf("%s",s);
n = strlen(s);
for(int i = 0;i<n;i++)
{
d[i] = s[n-i-1]-'0';
}
}
BigNum operator*(const BigNum &b)
{
BigNum c;
for(int i = 0;i<n;i++)
{
int num = i;
for(int j = 0;j<b.n;j++)
{
c.d[i+j] += d[i]*b.d[j];
if(c.d[i+j]>9)
{
c.d[i+j+1] = c.d[i+j]/10;
c.d[i+j]%=10;
}
num++;
}
if(c.d[b.n+i+1])
{
num++;
}
c.n += num-c.n; //这里等效c.n=num,但是num是下标，c.n是长度但num是下标
}
return c;
}
};
int main()
{
BigNum a,b;
a.read();
b.read();
BigNum c = a*b;
for(int i = c.n-1;i>=0;i--)
{
cout << c.d[i];
}
return 0;
}@TripFriend1130