50pts求调，回复必关

xuzhengfei666 @ 2025-01-10 19:28:44

#include<bits/stdc++.h>
using namespace std;
int n,cnt,a[1005];
int main()
{
    cin>>n;
    for(int i=1;i<=n;i++)
    {
        cin>>a[i];
    }
    for(int i=1;i<=n;i++)
    {
        for(int j=i+1;j<=n;j++)
        {
            if(sqrt(a[i]+a[j])*sqrt(a[i]+a[j])==(a[i]+a[j]))
                cnt++;
        }
    }
    cout<<cnt;
    return 0;
}

by chengjindong @ 2025-01-10 19:57:45

by chengjindong @ 2025-01-10 19:58:50

sqrt 前方个强制转换，换成整数

#include<bits/stdc++.h>
using namespace std;
int n,cnt,a[1005];
int main()
{
    cin>>n;
    for(int i=1;i<=n;i++)
    {
        cin>>a[i];
    }
    for(int i=1;i<=n;i++)
    {
        for(int j=i;j<=n;j++)
        {
            if((int)sqrt(a[i]+a[j])*(int)sqrt(a[i]+a[j])==(a[i]+a[j]))
                cnt++;
        }
    }
    cout<<cnt;
    return 0;
}

@xuzhengfei666

by chengjindong @ 2025-01-10 19:59:48

等会儿，我眼瞎了，就是 i+1

#include<bits/stdc++.h>
using namespace std;
int n,cnt,a[1005];
int main()
{
    cin>>n;
    for(int i=1;i<=n;i++)
    {
        cin>>a[i];
    }
    for(int i=1;i<=n;i++)
    {
        for(int j=i+1;j<=n;j++)
        {
            if((int)sqrt(a[i]+a[j])*(int)sqrt(a[i]+a[j])==(a[i]+a[j]))
                cnt++;
        }
    }
    cout<<cnt;
    return 0;
}

by xuzhengfei666 @ 2025-01-10 20:19:42

@chengjindong 谢谢