80分求解错！！！

B3849 [GESP样题 三级] 进制转换

hby110 @ 2025-01-12 19:12:24

能不能帮忙Debug一下！！谢谢了

#include<iostream>
#include<cmath>
#include<cstring>
using namespace std;
string s="0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
int main(){
    int t,r,n,m=0,i;
    int a[1000];
    memset(a,0,sizeof(a));
    cin>>t>>r;
    m=0;
    if(t<r){
        cout<<t;
    }else{
        while(t>r){
        if(t/r<r){
            n=t/r;
        }
        m++;
        a[m]=t%r;
        t/=r;
        }
        cout<<n;
        for(i=m;i>=1;i--){
            cout<<s[a[i]];
        }
    }
    return 0;
}

by 4041nofoundGeoge @ 2025-01-12 19:18:18

@hby110能不能写简单一点？

#include <bits/stdc++.h>
using namespace std;
char a[2222]={'0','1','2','3','4','5','6','7','8','9','A','B',
'C','D','E','F','G','H','I','J','K','L','M','N','O','P',
'Q','R','S','T','U','V','W','X','Y','Z'};
int main()
{
    int n,r;
    cin>>n>>r;
    string s;
    while(n!=0){
        s+=a[n%r];
        n=(n-n%r)/r;
    }
    reverse(s.begin(),s.end());
    cout<<s;
    return 0;
}
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