```cpp
#include <bits/stdc++.h>
using namespace std;
int main(){
unsigned long long int x,n,s=1;
cin>>x>>n;
x++;
for(int i=1;i<=n;i++)s*=x;
cout<<s;
return 0;
}
这个程序就过了，可能你输入输出格式不太对
```
by Amphetamine @ 2017-05-01 21:00:03
unsigned long long的输出格式为"%llu"
by Farblos @ 2017-05-21 21:40:01
@[陆仁贾](/space/show?uid=29883) 明明是%lld
by justforfun @ 2017-06-04 14:26:22
@[木木666](/space/show?uid=37243) 那是long long
by Farblos @ 2017-06-04 17:27:35
```cpp
#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
unsigned long long x,n,a,i;
int main(){
scanf("%lld %lld",&x,&n);
a=1;
for(i=1;i<=n;i++){
a=a*(x+1);
}
printf("%lld",a);
return 0;
}//%lld可以过
```
by justforfun @ 2017-06-05 22:43:09
@[陆仁贾](/space/show?uid=29883)
by justforfun @ 2017-06-05 22:50:47
@[木木666](/space/show?uid=37243) 并不是输出格式必须与变量类型相同，scanf相当于以与输出格式相同的变量类型输出，也就是说就算你用%d也能输出，只不过不大于2^31-1（int类型最大值）；
by Farblos @ 2017-06-09 18:50:18