sygzzyr @ 2019-07-03 17:53:10
using namespace std; int main() { char c1[100],c2[100]; int n,i=0,l;
scanf("%d%s",&n,c1);
n%=26;
l=strlen(c1);
for(i=0;i<l;i++)
{
c2[i]=c1[i]+n;
if(c2[i]>'z')
c2[i]-=26;
printf("%c",c2[i]);
}
return 0;
}
by infinities @ 2019-07-03 18:41:34
for(int i=0;i<n;i++){
in[j]++;
if(in[j]>'z')in[j]='a';//逐位累加再判断
}cout<<in[j];
by infinities @ 2019-07-03 18:41:54
这样就没问题了
by infinities @ 2019-07-03 18:41:58
@sygzzyr
by infinities @ 2019-07-03 18:43:59
好了不说了我先去解决作业了
不然我可能会被活活打死
by sygzzyr @ 2019-07-03 18:44:05
@装弱是种美德 是吼,大佬就是大佬(佩服)
by infinities @ 2019-07-03 18:44:57
@sygzzyr 哪里哪里,是您过谦了
by infinities @ 2019-07-03 18:45:12
溜了~~
by sygzzyr @ 2019-07-03 18:47:47
@装弱是种美德 拜拜,大佬也要加油解决作业呀~
by infinities @ 2019-07-03 18:49:57
rt
by infinities @ 2019-07-03 18:50:34
while(1)NOIP2019 RP++,score++;