KaenbyouRin @ 2019-07-12 16:11:27
#include <iostream>
#include <queue>
#include <algorithm>
using namespace std;
int dp[105][105], r, c, ans = -1, dx[4] = { 1, -1, 0, 0 }, dy[4] = { 0, 0, 1, -1 };
bool v[105][105];
long long g[105][105];
inline bool legal(const int x, const int y) {
return x >= 0 && x < r && y >= 0 && y < c;
}
struct St {
int x, y;
};
int main() {
ios::sync_with_stdio(false);
cin >> r >> c;
for (int i = 0; i < r; ++i) {
for (int j = 0; j < c; ++j) {
dp[i][j] = 1;
}
}
for (int i = 0; i < r; ++i)
for (int j = 0; j < c; ++j) {
cin >> g[i][j];
}
queue<St> q;
for (int i = 0; i < r; ++i) {
for (int j = 0; j < c; ++j) {
q.push({ i, j });
}
}
while (!q.empty()) {
St f = q.front();
q.pop();
ans = max(ans, dp[f.x][f.y]);
v[f.x][f.y] = false;
for (int i = 0; i < 4; ++i) {
int x = f.x + dx[i], y = f.y + dy[i];
if (legal(x, y) && g[x][y] < g[f.x][f.y] && dp[x][y] < dp[f.x][f.y] + 1) {
dp[x][y] = dp[f.x][f.y] + 1;
if (!v[x][y]) {
v[x][y] = true;
q.push({ x, y });
}
}
}
}
cout << ans;
}
by KaenbyouRin @ 2019-07-12 16:12:53
原本卡第二个点的。
by 幻之陨梦 @ 2019-07-12 16:20:52
@KaenbyouRin 这题应该用深搜剪枝吧。
by 幻之陨梦 @ 2019-07-12 16:21:27
并附上我的AC代码
#include<bits/stdc++.h>
using namespace std;
int r,c;
int a[105][105],l[105][105];
int dx[]={-1,0,1,0},dy[]={0,1,0,-1};
int dfs(int x,int y)
{
int nx,ny;
if(l[x][y]>0) return l[x][y];
int ans=1;
for(int i=0;i<4;i++)
{
nx=x+dx[i],ny=y+dy[i];
if(nx>=1&&nx<=r&&ny>=1&&ny<=r&&a[x][y]>a[nx][ny]) ans=max(dfs(nx,ny)+1,ans);
}
l[x][y]=ans;
return ans;
}
int main(void)
{
int i,j,maxn=-1;
scanf("%d%d",&r,&c);
for(i=1;i<=r;i++) for(j=1;j<=c;j++) scanf("%d",&a[i][j]);
for(i=1;i<=r;i++) for(j=1;j<=c;j++) maxn=max(maxn,dfs(i,j));
printf("%d",maxn);
}
by liukairui @ 2019-08-13 14:46:21
同BFS
by liukairui @ 2019-08-13 14:48:35
老哥解决了吗?
by LegendN @ 2020-03-13 19:37:00
我觉得是这一步剪枝了一小部分
判断条件里面
dp[x][y] < dp[f.x][f.y] + 1