天下第一 @ 2019-07-24 14:12:58
#include <iostream>
using namespace std;
int main()
{
int n,k,sum=0;
cin>>n>>k;
sum+=n;
if(n/k>k)
sum+=n/k/k;
else
if(n/k==k)
sum+=n/k+1;
else
sum+=n/k;
cout<<sum;
return 0;
}
by 学而思李老师 @ 2019-07-24 14:36:46
直接用数学做:
#include <cstdio>
using namespace std;
int main(){
int n, k;
scanf("%d %d", &n, &k);
printf("%d", n + (n - 1) / (k - 1));
return 0;
}
by wypdyxfor163 @ 2019-07-24 15:30:50
@社会我猪酐 在吗