陈俊熙abc123 @ 2017-05-24 16:39:14
var
a:array[1..1000] of longint;
i,j,n,m:longint;
begin
for i:=1 to 10 do
read(a[i]);
read(n);
for i:=1 to 10 do
if n+30>=a[i] then inc(m);
write(m);
end.
by Pascal周逸非 @ 2017-05-24 20:18:22
浪费内存,直接用10个存的数组就行了
const n=10;
var
a:array[1..n] of longint;
max,i,s:longint;
begin
for i:=1 to n do begin
read(a[i]);
end;
readln(max);
for i:=1 to n do begin
if a[i]<=(max+30) then s:=s+1;
end;
writeln(s);
end.
by 20041018xx @ 2017-06-02 21:52:31
const n=10;
var
a:array[1..n] of longint;
max,i,s:longint;
begin
for i:=1 to n do begin
read(a[i]);
end;
readln(max);
for i:=1 to n do begin
if a[i]<=(max+30) then s:=s+1;
end;
writeln(s);
end.
by 飞天者 @ 2017-06-03 20:24:00
@kkksc03
有人发答案!!!