80分，求大佬帮助，感谢

zrf1170375918 @ 2019-08-20 21:01:04

#include <stdio.h>
#include <stdlib.h>

int main()
{
long int in;
int a[10]={0},i=0,pv;

scanf("%ld",&in);
pv=labs(in);
if(pv>0)
{
    while(pv>0)
    {
        a[i]=pv%10;
        pv/=10;
        i++;
    }
    if(in<0)
    {
        printf("-");
    }
    if(a[0]!=0)
    {
        printf("%d",a[0]);
    }
    for(int j=1;j<i;j++)
    {
        printf("%d",a[j]);
    }
}
else
{
    printf("0");
}
return 0;
}

by SJC_03 @ 2019-08-20 21:07:41

@zrf1170375918

你试试这个数据:

20000

应输出:

2

你的输出:

0002

by SJC_03 @ 2019-08-20 21:08:59

您应该去除所有的前导0

by mtz_FWB @ 2019-08-20 21:18:33

include<bits/stdc++.h>

using namespace std;

int main(){

long long n,w,s=0;
cin>>n;
while(n!=0){
  w=n%10;
  s=s*10+w;
  n=n/10;
}
cout<<s;

}

by zrf1170375918 @ 2019-08-20 21:48:35

@SJC_03 明白了，谢谢大佬

by JamesMessi @ 2019-08-21 11:13:46

#include<bits/stdc++.h>
using namespace std;
int a[1000];
int dao(int n){
    int s=0;
    while (n!=0){
        s=s*10+n%10;
        n=n/10;
    }
    return s;
}
int main(){
    int n;
    cin>>n;
    cout<<dao(n);
    return 0;
}