1melon @ 2019-11-10 11:11:09
#include<stdio.h>
int main(){
int a,b,c,t;
int n,m,l,k;
int num[1000];
scanf("%d%d%d",&a,&b,&c);
for ( n = 123; n < 987; n++)
{
m = n/a*b;
l = n/a*c;
if ((n/100+n/10%10+n%10+m/100+m/10%10+m%10+l/100+l/10%10+l%10==1+2+3+4+5+6+7+8+9)
&&((n/100)*(n/10%10)*(n%10)*(m/100)*(m/10%10)*(m%10)*(l/100)*(l/10%10)*(l%10)==1*2*3*4*5*6*7*8*9))
{
if(n>m){
k = n;
m = n;
m = k;
}
if(m>l){
k = m;
l = m;
l = k;
}
printf("%d %d %d",n,m,l);
t++;
}
}
if(t==0) printf("No!!!");
return 0;
}
by awa再也不水贴 @ 2019-11-10 11:22:43
优秀,等下,我思路跟你一样
by awa再也不水贴 @ 2019-11-10 11:23:19
#include <iostream>
using namespace std;
int main()
{
double A,B,C;
cin>>A>>B>>C;
int a=123;
int b,c,i=0;
while (a<=329)
{
b=B/A*a;
c=C/A*a;
if(
(
a%10+a/10%10+a/100+b%10+b/10%10+b/100+c%10+c/10%10+c/100
==
1+2+3+4+5+6+7+8+9
)
&&
(
(a%10)*(a/10%10)*(a/100)*(b%10)*(b/10%10)*(b/100)*(c%10)*(c/10%10)*(c/100)
==
1*2*3*4*5*6*7*8*9
)
)
{
cout<<a<<" "<<b<<" "<<c<<endl;
i++;
}
a++;
}
if(i==0) cout<<"No!!!";
return 0;
}
by awa再也不水贴 @ 2019-11-10 11:23:49
@1melon 请自动无视括号缩进大法
by 1melon @ 2019-11-10 23:54:49
@xiaojie233a 不懂为啥第一个和最后一个点过不了 我再康康
by awa再也不水贴 @ 2019-11-11 21:42:33
@1melon 卧。。。。。艹
12点