Coding_godnice20 @ 2020-01-24 15:24:26
#include<stdio.h>
#include<string.h>
int main()
{
char str[500];//定义一个字符串存储原文字符串
int n = 0;//定义一个int类型的变量存储n的值
scanf_s("%d", &n);
scanf_s("%s", &str,40);
int length;//定义一个length表示原字符串的长度
length = strlen(str);
for (int i = 0; i < length; i++)
{
if ((str[i] + n) > 122)
{
str[i] = '`' + (str[i]+n) - 122;
}
else if ((str[i] + n) <= 122)
{
str[i] = str[i] + n;
}
}
printf("%s", str);
}
by tangrunxi @ 2020-01-24 15:33:10
@Coding_godnice20 出门右转题解区提交,不谢
by CrTsIr400 @ 2020-01-24 15:35:32
@Coding_godnice20 出门右转题解区提交,不谢
by 1kri @ 2020-01-24 15:37:35
太强了%%%
by DeepSkyBlue__ @ 2020-01-24 15:42:38
这题还收题解吗qwq
by Zyque @ 2020-01-24 16:02:23
爬