杜雨峰 @ 2020-03-07 11:04:59
#include <iostream>
using namespace std;
int main()
{
int i,n,k,m=1;
cin>>k;
for(i=2;m<k;i++)
{
m+=1/i;
}
cout<<i;
return 0;
}
by Flash1ng @ 2020-03-07 11:07:22
#include<bits/stdc++.h>
using namespace std;
long long k,i;
double s=0.0;
int main() {
cin >> k;
for (i=1; s<=k; i++)
s=s+1.0/i;
cout << i-1;
return 0;
}
by 杜雨峰 @ 2020-03-07 11:07:32
求回复
by jijidawang @ 2020-03-07 11:08:19
@杜雨峰 用double
by jijidawang @ 2020-03-07 11:08:39
@杜雨峰 你改成1.0/i,要不然整形都是0
by SIXIANG32 @ 2020-03-07 11:11:09
@杜雨峰 整形您敢做?
by 杜雨峰 @ 2020-03-07 11:14:12
谢谢大家!
by Clintikas97 @ 2020-03-07 11:21:09
double了解一下