怎么优化啊？？？

W_churchill @ 2020-03-31 22:44:23

#include<bits/stdc++.h>
using namespace std;
int a[5000010];
int main()
{
    register int n,k;
    cin>>n>>k;  
    for(int i=0;i<n;i++)
        cin>>a[i];
    sort(a,a+n);
    cout<<a[k];
    return 0;
}

by 警策看取 @ 2020-03-31 22:45:28

加上快读和O2才能A。

by Hexarhy @ 2020-03-31 22:47:32

@Qinclude 用scanf

或者关闭同步

by tZEROちゃん @ 2020-03-31 22:47:52

开 O2 即可。

by tZEROちゃん @ 2020-03-31 22:49:16

然后把 cin/cout 改成 scanf/printf

by UnyieldingTrilobite @ 2020-03-31 22:54:01

@Qinclude nth_element

by Steven__Chen @ 2020-03-31 23:05:28

@Qinclude 手写个堆/xyx

by W_churchill @ 2020-04-01 09:43:12

@tearing scanf/printf不会啊本人比较菜

by W_churchill @ 2020-04-01 09:47:35

是不是这么写的啊？

scanf("%d%d",&n,&k);
printf("%d",&a[k]);

好像错了

by 花田汐 @ 2020-04-01 11:33:48

@Qinclude printf不用取地址，printf("%d",a[k]);即可~

by 花田汐 @ 2020-04-01 11:49:00

看到楼主排序完就直接输出a[k]才发现——原来这题没有重复数字的啊喂！QWQ

我还以为排完序是1 1 1 2 2 3 3 3 3 这样……