召唤师昧光 @ 2017-09-11 22:11:48

#include <stdio.h>
int main()
{
    short int k,n;
    double sn=0;
    scanf("%d",&k);
    for(n=1;sn<k;n++){
        sn=sn+(1/n);
    }
    printf("%d",n-1);
    return 0;
}

by Administrator2004 @ 2017-09-11 22:29:56

把short改成int

by 召唤师昧光 @ 2017-09-12 21:35:50

@Administrator2004 不行啊，改完以后超时了

by 召唤师昧光 @ 2017-09-13 21:47:24

别沉

by 召唤师昧光 @ 2017-09-16 21:19:41

没有人吗，为什么总是tle

by Lyricle @ 2017-09-16 22:29:40

Shortint是过不去咩

by 上官小胖 @ 2017-09-17 14:29:15

sn=sn+(1.00000000000000000/n);

输出改成n；

先弄个死循环，再循环里判断是否break

by 上官小胖 @ 2017-09-17 14:30:04

sn=sn+(1.00000000000000000/n);

输出改成n；

先弄个死循环，再循环里判断是否break

by 上官小胖 @ 2017-09-17 14:30:51

#include <bits/stdc++.h>
using namespace std;
double x;
long long n,ans=1;
int main()
{
    cin>>n;
    for (;;ans++)
    {
        x+=(1.00000000000000000/ans);
        if (x>n)
            break;
    }
    cout<<ans<<endl;
    return 0;
}