ethan01 @ 2020-04-21 22:18:55
#include<stdio.h>
int main()
{
int num;
int i,t;
char number[103];
char pic[10][6][4]={" ",
"XXX",
"X.X",
"X.X",
"X.X",
"XXX",
" ",
"..X",
"..X",
"..X",
"..X",
"..X",
" ",
"XXX",
"..X",
"XXX",
"X..",
"XXX",
" ",
"XXX",
"..X",
"XXX",
"..X",
"XXX",
" ",
"X.X",
"X.X",
"XXX",
"..X",
"..X",
" ",
"XXX",
"X..",
"XXX",
"..X",
"XXX",
" ",
"XXX",
"X..",
"XXX",
"X.X",
"XXX",
" ",
"XXX",
"..X",
"..X",
"..X",
"..X",
" ",
"XXX",
"X.X",
"XXX",
"X.X",
"XXX",
" ",
"XXX",
"X.X",
"XXX",
"..X",
"XXX"};
scanf("%d",&num);
for (i = 0;i <= num;i++){
scanf("%c",&number[i]);
}
for (i = 1;i <= num;i++){
t = number[i] - '0';
printf("%c%c%c",pic[t][1][0],pic[t][1][1],pic[t][1][2]);
if(i < num){
printf(".");
}
else{
printf("\n");
}
}
for (i = 1;i <= num;i++){
t = number[i] - '0';
printf("%c%c%c",pic[t][2][0],pic[t][2][1],pic[t][2][2]);
if(i < num){
printf(".");
}
else{
printf("\n");
}
}
for (i = 1;i <= num;i++){
t = number[i] - '0';
printf("%c%c%c",pic[t][3][0],pic[t][3][1],pic[t][3][2]);
if(i < num){
printf(".");
}
else{
printf("\n");
}
}
for (i = 1;i <= num;i++){
t = number[i] - '0';
printf("%c%c%c",pic[t][4][0],pic[t][4][1],pic[t][4][2]);
if(i < num){
printf(".");
}
else{
printf("\n");
}
}
for (i = 1;i <= num;i++){
t = number[i] - '0';
printf("%c%c%c",pic[t][5][0],pic[t][5][1],pic[t][5][2]);
if(i < num){
printf(".");
}
}
return 0;
}
by ethan01 @ 2020-04-21 22:19:33
如题,萌新暴风哭泣,求解答
by Trinitrotoluene @ 2020-04-21 22:22:08
@ethan01 '/n' 被宁吃了?
by ethan01 @ 2020-04-22 08:44:20
@Trinitrotoluene 哪个\n,能不能说详细一点鸭
by Trinitrotoluene @ 2020-04-22 09:38:02
@ethan01 所有的 '/n' 都被 "scanf("%c")" 读进去了
by ethan01 @ 2020-04-22 10:08:28
@Trinitrotoluene 我还是不太明白。我觉得第一个数字之后的\n被存到number[0]里面了,右面的调用是从number[1]开始的,这样不是相当于屏蔽掉了回车的影响了吗
by Trinitrotoluene @ 2020-04-22 10:37:00
@ethan01 你用 "scanf("%s")" 吧,要不然用 cin 算了
by ethan01 @ 2020-04-22 11:34:44
@Trinitrotoluene 用%s肯定能过,我就是想不明白%c的那个错在哪里了
by Trinitrotoluene @ 2020-04-22 11:48:14
@ethan01 数据换行有时 '/n' 有时 '/r/n',你要是不确定的话就到 IDE 上试试
by Trinitrotoluene @ 2020-04-22 11:48:30
你的代码我在 IDE 上运行了1分钟都没有输出答案