Reobrok_Kk @ 2020-08-10 16:08:46
#include<algorithm>
#include<iostream>
#include<string>
#include<cstdio>
using namespace std;
int a[5001],b[5001];
int f[5001][5001];
int max(int x,int y){return x>y?x:y;}
int main(){
int n;
cin>>n;
for(int i=1;i<=n;i++) cin>>a[i];
for(int i=1;i<=n;i++) cin>>b[i];
for(int i=1;i<=n;i++)
for(int j=1;j<=n;j++)
{
if(a[i]==b[j]) f[i][j]=f[i-1][j-1]+1;
if(a[i]!=b[j]) f[i][j]=max(f[i][j-1],f[i-1][j]);
}
cout<<f[n][n]<<endl;
return 0;
}
by 天有不测风云 @ 2020-08-10 16:10:17
你才学到完全背包啊…………
by 天有不测风云 @ 2020-08-10 16:12:36
emmmm
by X2H_tato @ 2020-08-10 16:18:45
@俺太难了 O(n*n)过不了啊
by X2H_tato @ 2020-08-10 16:19:22
写正解吧
by Reobrok_Kk @ 2020-08-10 16:19:27
求dalao O(n log n) 解法思路
by Reobrok_Kk @ 2020-08-10 16:22:17
@高高苦力怕 求正解思路
by X2H_tato @ 2020-08-10 16:22:21
@俺太难了 这个挺好的
by Reobrok_Kk @ 2020-08-10 16:24:32
@高高苦力怕 蟹蟹dalao
orz orz orz %%%
by Dovuq @ 2020-12-25 20:15:41
246810
by Miraii @ 2021-02-19 10:54:33
烤咕,orz已成为dalao的@neach_joup