为什么只对20

Alien_99 @ 2016-02-20 11:20:27

#include<stdio.h>
int main(){
int n,a,b,c,d;
scanf("%d",&n);
a=n/100;
b=(n/10)%10;
c=n%10;
d=c*100+b*10+a;
printf("%d",d);
return 0 ;
}

by CInDY @ 2016-02-20 11:25:40

因为并不是所有数据都为三位数……

by Alien_99 @ 2016-02-20 11:27:31

欧。。。。。

by CInDY @ 2016-02-20 11:29:36

我用pascal打的，虽然水平不高。

[codep]

program P1307;
 var
  a:string;
  i,j:integer;
 begin
  readln(a);
  if a='0' then
   begin
    writeln('0');
    exit;
   end;
  if a[1]='-' then write('-');
  j:=0;
  for i:=length(a) downto 1 do
   if a[i]='0' then j:=j+1
   else break;
  for i:=length(a)-j downto 1 do if a[i]<>'-' then write(a[i]);
  writeln;
 end.
[/codep]

by kongksora @ 2016-02-20 12:19:48

[codec]

#include<iostream>
#include<string>
using namespace std;
int main()
{
    string a,b="";
    cin>>a;
    if(a[0]=='-'){cout<<'-';a.erase(0,1);}
    while(a!="")
    {
        b+=a[a.size()-1];
        a.erase(a.size()-1,1);
    }
    while(b[0]=='0'&&b!="0")b.erase(0,1);
    cout<<b;
}
[/codec]

by Hyle33ies @ 2016-02-20 19:08:45

你这个是三位数吧

by Blue_water @ 2016-03-03 12:38:30

我是这样做的：

var st:string;
    i,t:longint;
begin
  readln(st);
  if st[1]='-' then begin delete(st,1,1); st:=st+'-'; end;
  for i:=length(st) downto 1 do
  begin
    if (st[i]<>'0') and (t=0) and (st[i]<>'-') then begin write(st[i]);t:=1; end else
    if (t=1) or (st[i]='-') then write(st[i]);
  end;
end.