CY666 @ 2020-10-16 00:02:24
#include<bits/stdc++.h>
using namespace std;
int n;
int a[10001];
double ans;
int main()
{
cin>>n;
for(int i=1;i<=n;i++)
cin>>a[i];
sort(a+1,a+n+1);
for(int i=2;i<=n-1;i++)
{
ans+=a[i];
}
printf("%.2lf",ans/(n-2));
return 0;
}
为什么sort括号里面不加1会由两个wa
by 已注销yj!gBUM @ 2020-10-16 00:03:53
数组下标的问题
默认的话是从0开始
by TKater_yzt @ 2020-10-16 00:45:06
不加1你排的是0~n-1中的数
by cxqghzj @ 2020-10-16 07:16:27
2楼正解
实际上不需要排序的
只需要算出最大和最小
把全部的加起来再减去最大和最小就行了
by cxqghzj @ 2020-10-16 07:17:05
我的代码/xyx
#include <iostream>
#include <cstdio>
using namespace std;
int main(){
int n,s[1001] = {0},maxn = -1,minn = 11;
double h = 0;
cin >> n;
for (int i = 0;i < n;i++){
cin >> s[i];
maxn = max(s[i],maxn);
minn = min(s[i],minn);
h += s[i];
}
h -= maxn;
h -= minn;
h = h / (n - 2);
printf("%.2lf",h);
return 0;
}
by liuzimingc @ 2020-11-02 20:00:00
@CY666 数组范围不是0~n-1吗……
#include<cstdio>
int main(){
int n,max=-100,min=100,tot=0;
scanf("%d",&n);
int a[n];
for (int i=0;i<n;i++)
{
scanf("%d",&a[i]);
tot+=a[i];
if (a[i]>max)
max=a[i];
if (min>a[i])
min=a[i];
}
printf("%.2lf",(tot-max-min)*1.0/(n-2));
return 0;
}