80分求助

KobeBeanBryant @ 2020-12-25 18:38:19

#include<bits/stdc++.h>
using namespace std;
int n;
string s;
int main(){
    cin>>n;
    cin>>s;
    if(n==26){
        cout<<s;
        return 0;
    }
    for(int i=0;i<s.length();i++){

        if(s[i]+n>122) {s[i]='a'+('z'-n)%26;continue;}
        s[i]+=n;
        continue;

    }
    cout<<s;
}

by FCB_1899 @ 2020-12-25 19:01:38

你看看把 ('z'-n)%26 两边加上括弧试试

by FCB_1899 @ 2020-12-25 19:03:14

我的AC代码

#include<iostream>
#include<string>
#include<cstring>
using namespace std;

int main()
{
    string s;
    int n;
    cin>>n;
    cin>>s;
    int l=s.size();
    for(int i=0;i<l;i++)
        s[i]=s[i]-'a';
    for(int i=0;i<l;i++)
        s[i]=(s[i]+n)%26;
    for(int i=0;i<l;i++)
        s[i]=s[i]+'a';
    cout<<s;
    return 0;
}

你看看

by FCB_1899 @ 2020-12-25 19:04:54

@ KobeBeanBryant

by KobeBeanBryant @ 2020-12-26 09:49:32

谢谢大佬