C语言：全部RE？本地可以跑

C_vegetable @ 2021-01-15 16:52:29

#include <stdio.h>
#include <string.h>
struct stu
{
    char name[9];
    int chinese;
    int math;
    int english;
    int average;
};
int main()
{
    struct stu grade[1000];
    int n,i,max,i1;
    scanf("%d",&n);getchar();
    for(i=0;i<n;i++)
    {
        scanf("%s",grade[i].name);
        scanf("%d%d%d",&grade[i].chinese,&grade[i].math,&grade[i].english);
        getchar();
        grade[i].average=(grade[i].chinese+grade[i].math+grade[i].english);
    }
    max=grade[0].average;
    for(i=1;i<n;i++)
    if(grade[i].average>max)
    {
        max=grade[i].average;
        i1=i;
    }
    printf("%s %d %d %d",grade[i1].name,grade[i1].chinese,grade[i1].math,grade[i1].english);
}

by CGDGAD @ 2021-01-15 16:58:46

@C_vegetable 给i1一个初值亲测可以通过

by CGDGAD @ 2021-01-15 16:59:33

int n,i,max,i1 \ \ \textbf{=0};

by 永动姬 @ 2021-01-15 17:02:59

@C_vegetable

Re老正常了，多试试就阔以了（应该吧）

给你附上没有Re的代码：

#include<bits/stdc++.h>
using namespace std;
struct xm{
    string s;
    int x;
    int y;
    int z;
}a[1004]; 
int b[1004];
int main(){
    int n;
    cin>>n;
    for(int i=0;i<n;i++){
        cin>>a[i].s>>a[i].x>>a[i].y>>a[i].z;
        b[i]=a[i].x+a[i].y+a[i].z;
    }
    for(int i=0;i<n;i++){
        int c=0;
        if(b[c]>=b[i]){
            cout<<a[c].s<<' '<<a[c].x<<' '<<a[c].y<<' '<<a[c].z;
            break;
        }
        else{
            c++;
        }
    }
    return 0;
}

by C_vegetable @ 2021-01-16 09:11:02

@NSObject ！哦对呀！大师，我悟了 感谢感谢感谢

by C_vegetable @ 2021-01-16 09:11:42

@羽翼喵呀 好的好的，感谢dalao！