Mr_hua666 @ 2021-01-19 12:15:30
#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
int main() {
char c[100] = { 0 };
int n=0;
cin >> n;
if (n > 25) n = (n - (n - 1) / 25) % 25;
for (int i = 0; i <= 99; i++)
{
cin >> c[i];
if (int(c[i] + n) <= 122)
cout << char(c[i] + n);
else cout << char(c[i] + n - 26);
}
return 0;
}
by DWT8125 @ 2021-01-19 12:24:20
重复100次输入???
by LHQing @ 2021-01-19 12:25:41
#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
int main() {
char c[100] = { 0 };
int n=0;
cin >> n;
if (n > 25) n = (n - (n - 1) / 25) % 25;
scanf("%s",c);
for (int i = 0; i < strlen(c); i++)
{
if (int(c[i] + n) <= 122)
cout << char(c[i] + n);
else cout << char(c[i] + n - 26);
}
return 0;
}
by LHQing @ 2021-01-19 12:25:56
@Mr_hua666 你那个输入完了不结束不行
by LHQing @ 2021-01-19 12:26:40
@Mr_hua666 你看你自己运行一下,他输出了rxf不结束
by Mr_hua666 @ 2021-01-19 12:27:02
换成这样就对了
#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
int main() {
char c[100] = { 0 };
int n=0;
cin >> n;
if (n > 25) n = (n - (n - 1) / 25) % 25;
cin >> c;
for (int i = 0; c[i]!='\0'; i++)
{
if (int(c[i] + n) <= 122)
cout << char(c[i] + n);
else cout << char(c[i] + n - 26);
}
return 0;
}
可是我觉得重复应该也没毛病吧? 谢谢大佬
by LHQing @ 2021-01-19 12:27:50
@Mr_hua666 他运行完了要结束,你不结束当然会错
by Mr_hua666 @ 2021-01-19 12:28:08
@LHQing 谢谢大佬!!
by LHQing @ 2021-01-19 12:37:17
@Mr_hua666 可以打开我的主页点关注哦