像素旋转 @ 2021-01-31 14:04:13
#include<iostream>
#include<string>
#include<algorithm>
using namespace std;
const int N = 1000;
class Student {
public:
char name[9];
int chinese;
int math;
int english;
Student() {
name[0] = '0';
chinese = 0;
math = 0;
english = 0;
sum = 0;
};
int summary() {
return sum=chinese + math + english;
}
private:
int sum;
};
int main(void)
{
int n;
cin >> n;
cin.get();
Student** stu;
stu = new Student*[n];
int* sum = new int[n];
int max = 0;
int ans = 0;
for (auto i = 0; i < n; i++){
cin >>stu[i]->name>>stu[i]->chinese >> stu[i]->math >> stu[i]->english;
sum[i]=stu[i]->summary();
if (max < sum[i]) {
max = sum[i];
ans = i;
}
}
cout << stu[ans]->name << " " << stu[ans]->chinese
<< " " << stu[ans]->math << " " << stu[ans]->english << endl;
return 0;
}by JohnFKennedy @ 2021-02-02 18:14:17
@像素旋转 别的题估计能过
by Deep_Breath @ 2021-04-25 20:37:45
可以直接用结构体啊？ AC code：
#include <bits/stdc++.h>
#define LL long long
using namespace std;
int const N = 100000 + 5;
/*数组开外面*/
struct s {
string xm;
int yw, sx, yy;
};
int main () {
int i, n;
s mx, p;
mx.yw = 0;
mx.sx = 0;
mx.yy = 0;
cin >> n;
while (n--) {
cin >> p.xm >> p.yw >> p.sx >> p.yy;
if (p.yw + p.sx + p.yy > mx.yw + mx.sx + mx.yy) {
mx = p;
}
}
cout << mx.xm << " " << mx.yw << " " << mx.sx << " " << mx.yy;
return 0;
}