NaN_HQJ2007_NaN @ 2021-02-09 22:17:06
#include <bits/stdc++.h>
using namespace std;
const int N = 5e5 + 5;
int n, p;
int a[N], tmp[N];
long long sum = 0, s[4 * N];
long long pushup(int id) {
s[id] = s[id << 1] + s[id << 1 | 1];
}
void update(int id, int l, int r, int x) {
if (l == x && r == x) {
++s[id];
return;
}
int mid = (l + r) >> 1;
if (x <= mid) update(id << 1, l, mid, x);
else update(id << 1 | 1, mid +1, r, x);
pushup(id);
}
long long query(int id, int l, int r, int x, int y) {
if (x <= l && r <= y) return s[id];
int mid = (l + r) >> 1;
long long ans = 0;
if (x <= mid) ans += query(id << 1, l, mid, x, y);
if (y > mid) ans += query(id << 1 | 1, mid + 1, r, x, y);
return ans;
}
int main() {
register int i;
scanf("%d", &n);
for (i = 1; i <= n; ++i) {
scanf("%d", &a[i]);
tmp[i] = a[i];
}
sort(tmp + 1, tmp + n + 1);
p = unique(tmp + 1, tmp + n + 1) - (tmp + 1);
for (i = 1; i <= n; ++i) a[i] = lower_bound(tmp + 1, tmp + p + 1, a[i]) - tmp;
for (i = n; i > 1; --i) {
update(1, 1, p, a[i]);
sum += query(1, 1, p, 1, a[i - 1] - 1);
}
printf("%lld\n", sum);
return 0;
}
by NaN_HQJ2007_NaN @ 2021-02-09 22:28:13
哦,不用了,我知道了