0分求助

HgSO4_QwQ @ 2021-02-21 12:20:32

#include<iostream>
using namespace std;

int a,k,cnt,ans1,ans2;

int main()
{
    cin>>a>>k;
    for(int i=1;i<=a;i++)
    {
        if(i%k==0)
        {
            ans2+=i;
            cnt++;
        }
        else
        {
            ans1+=i;
        }
    }
    printf("%.1lf %.1lf",ans1/(a-cnt),ans2/cnt);
    return 0;
}

by 渡鸦2007 @ 2021-02-21 12:27:12

@Felder printf("%.1lf %.1lf",ans1/(a-cnt),ans2/cnt);改为printf("%.1lf %.1lf",double(ans1)/(a-cnt),double(ans2)/cnt);

by 渡鸦2007 @ 2021-02-21 12:28:27

@fqyz_wyc

你ans和cnt都是int类型，相除也是int类型，用%lf输出会类型错误

by 渡鸦2007 @ 2021-02-21 12:31:07

@Felder

然后`printf`应该用`<cstdio>`库，比赛中`<iostream>`并不包含`printf`

为什么会标记我没按要求使用Md啊

by HgSO4_QwQ @ 2021-02-21 12:32:54

谢谢大佬

by HgSO4_QwQ @ 2021-02-21 12:35:27

??40分

by HgSO4_QwQ @ 2021-02-21 12:37:01

@fqyz_wyc

by 渡鸦2007 @ 2021-02-21 12:38:36

@Felder 你前后输出反了

by HgSO4_QwQ @ 2021-02-21 12:39:00

O

by 渡鸦2007 @ 2021-02-21 12:39:54

@Felder 调整后可过

by HgSO4_QwQ @ 2021-02-21 12:41:06

/tmp/compiler_3aod8zqz/src: 在函数‘int main()’中: /tmp/compiler_3aod8zqz/src:21:12: 错误：unable to find string literal operator ‘operator""double’ with ‘const char [12]’, ‘long unsigned int’ arguments printf("%.1lf %.1lf"double(ans2)/cnt,double(ans1)/(a-cnt)); ^~~~~~~

?????