dreammer_mu @ 2021-03-31 14:37:29
#include <iostream>
#include <queue>
#define MAXN 1000
using namespace std;
int map[MAXN][MAXN];
int vis[MAXN][MAXN];
int sx[4]={1,-1,0,0};
int sy[4]={0,0,1,-1};
struct node{
int x,y,step;
}t1,t2;
queue <node> q;
void bfs(int a,int b,int c,int d,int n){
t1.x=a;t1.y=b,t1.step=0;
q.push(t1);
while(!q.empty()){
t1=q.front();
q.pop();
if(t1.x==c && t1.y==d){
cout<<t1.step<<endl;
return;
}
for(int i=0;i<4;i++){
t2.x=t1.x+sx[i];t2.y=t1.y+sy[i];t2.step=t1.step+1;
vis[t2.x][t2.y]=1;
q.push(t2);
if( map[t2.x][t2.y] == 1 || t2.x>n ||t2.x<=0||t2.y>n ||t2.y<=0 || vis[t2.x][t2.y]==1){
continue;
}
}
}
}
int main(){
int n;
cin>>n;
for(int i=0;i<n;i++){
for(int j=0;j<n;j++){
cin>>map[i][j];
}
}
int a,b,c,d;
cin>>a>>b>>c>>d;
bfs(a,b,c,d,n);
return 0;
}
脑袋要炸了,谢谢各位大佬
by metaphysis @ 2021-03-31 16:38:35
@dreammer_mu
输入时一个
by metaphysis @ 2021-03-31 16:46:32
@dreammer_mu
for(int i=0;i<4;i++){
t2.x=t1.x+sx[i];t2.y=t1.y+sy[i];t2.step=t1.step+1;
vis[t2.x][t2.y]=1;
q.push(t2);
if( map[t2.x][t2.y] == 1 || t2.x>n ||t2.x<=0||t2.y>n ||t2.y<=0 || vis[t2.x][t2.y]==1){
continue;
}
}
先置入队列再判断可能会造成 vis 数组发生越界。
by dreammer_mu @ 2021-05-09 20:04:43
@metaphysis 好的好的,谢谢大佬指点!