張懌宸Eason @ 2021-04-25 22:14:31

#include<bits/stdc++.h>
using namespace std;
char s[1000];
long long k;
int main()
{
    cin>>k>>s;
    for(int i=0;s[i];++i){
        s[i]+=k;
        if(s[i]>'z') s[i]+=-26;
    }
    cout<<s<<endl;
    return 0;
}

by qqqqq111 @ 2021-04-25 22:20:05

s的Ascll可能会超过ascll码的范围

by qqqqq111 @ 2021-04-25 22:21:12

@張懌宸Eason

by qqqqq111 @ 2021-04-25 22:21:44

而且k可能会超过100，需要将k %26

by 張懌宸Eason @ 2021-04-25 22:32:09

@qqqqq111 谢谢！！！

by qqqqq111 @ 2021-04-26 18:30:10

还没判断s[i]<'a'的情况呢

by coldy_rainy @ 2021-06-17 19:57:31

@qqqqq111 额额，题目中不是说“由不超过50个小写字母组成吗？”，这条代码多余了吧。

by qqqqq111 @ 2021-06-17 20:02:45

@penhaochen 不加会wa on #4