未知错误？

BabyChen @ 2021-05-08 18:31:07

#include<stdio.h>
#include<stdlib.h>

int main()
{
    double sn=0;

    int k,n;
    scanf("%d",&k);
    for (n=1;sn<=k;n++)
    {
        sn=sn+ 1/n; 
    }
    printf("%d",n);
    return 0;
}

by reailikezhu @ 2021-05-08 18:35:48

把 n 也定义成cdouble试试。

by 朦胧细雨 @ 2021-05-08 19:00:19

你要把“1/n”进行强行转换

sn=sn+(double)1/n;

然后你输出的n还要减一也就是

printf("%d",n-1);

by 力巴尔 @ 2021-05-30 13:43:23

把1 / n改成1.0 / n