hanran_ @ 2021-07-06 08:57:16
#include <iostream>
using namespace std;
string x,y;
int a[100001],b[100001],c[100001],la,lb,lc;
int main () {
cin >> x >> y;
la = x.length();
lb = y.length();
for (int i = 0; i < la; i++) {
a[la - i - 1] = x[i] - '0';
}
for (int i = 0; i < lb; i++) {
b[lb - i - 1] = y[i] - '0';
}
// for (int i = 0; i < la; i++) {
// cout << a[i];
// }
for (int j = 0; j < lb; j++) {
for (int i = 0; i < la; i++) {
c[i + j] += a[i] * b[j];
c[i + j + 1] +=(c[i + j] / 10);
c[i + j] =c[i + j] % 10;
}
}
lc = la + lb;
for (int i = lc; i >= 1; i--) {
if (c[i] != 0) {
break;
}
lc--;
}
for (int i = lc; i > 0; i--) {
cout << c[i];
}
return 0;
}
by GuaYsu @ 2021-07-27 19:17:50
输出的部分
for (int i = lc; i > 0; i--) {
cout << c[i];
}
循环中间的i>0改成i>=0即可。您这样相当于没有输出个位。修改后代码即可AC
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