蒟蒻求助！40分自己可能绕晕了没有排查出问题...

H_sDc_N @ 2021-08-05 23:15:53

#include <bits/stdc++.h>
using namespace std;
int main(){
  long long int i = 0 , day = 0 , sum = 0 , k;
  cin >> k;
  while (day < k) {
    i ++;day +=i ;
    for (int j = 1;j <= i; j++)
      sum += i;
  }
  printf("%lld\n", sum);
  return 0;
}

by dtrthg @ 2021-08-06 03:55:23

#include <bits/stdc++.h>
using namespace std;
int main(){
  long long int i = 0 , day = 0 , sum = 0 , k;
  cin >> k;
  while (true) {
    i ++;day +=i ;
    for (int j = 1;j <= i; j++)
      sum += i;
      if(day>k){
        sum=sum-(day-k)*i;
        break;
      }
  }
  printf("%lld\n", sum);
  return 0;
}

多算金币了，假如k=13，那么模拟一遍就会这样：

然鹅，金币多算了2天，这时要把多出的金币还回去。已知多拿了day-k天金币,每天多拿了i个金币，那多领了多少也就很好算了

by dtrthg @ 2021-08-06 03:56:15

@ H_sDc_N

by H_sDc_N @ 2021-08-11 17:57:59

谢谢您！orz @dtrthg

by 武意程wyc @ 2021-08-16 16:36:11

#include<iostream>
using namespace std;
int main()
{
    int n,i,s=0,a,b;
    cin>>n;
    a=1;
    b=0;
    for(i=1;i<=n;i++)
    {
        s=s+a;
        b=b+1;
        if(b == a)
        {
            b=0;
            a=a+1;
        }
    }
    cout<<s;
}

一种答案