谦上谦 @ 2021-08-17 15:42:15

#include<bits/stdc++.h>
using namespace std;
int n,t=1,s;
int main()
{
    cin>>n;
    for (int i=1;i<=n;)
    {
        for (int j=1;j<=t;j++)
        {

            s+=t,i++;
        }
        t++;
        if(i==n)
            break; 
    }
    cout<<s;
    return 0;
}

by Starlight_StationOI @ 2021-08-17 15:48:33

你输入5看看你就知道错哪儿了 正确输出是11

by NastiY_iN_saNitY @ 2021-08-17 15:49:44

#include <bits/stdc++.h>
using namespace std;

int main()
{
    int n,ans,i;
    cin>>n;
    for(i=1;i<=n;n-=i++)ans+=i*i;
    cout<<ans+i*n;
    return 0;
}

by Starlight_StationOI @ 2021-08-17 15:50:00

在j的循环内没有考虑j<t但i==n的情况

by NastiY_iN_saNitY @ 2021-08-17 15:50:22

思路参见第一篇题解

by Starlight_StationOI @ 2021-08-17 15:51:17

@谦上谦

by jyb666 @ 2021-08-17 15:51:35

@谦上谦

#include<bits/stdc++.h>
using namespace std;
int n,t=1,s;
int main()
{
    cin>>n;
    for (int i=1;i<=n;)
    {
        for (int j=1;j<=t;j++)
        {

            s+=t,i++;
            if(i>n)
                break; 
        }
        t++;
    }
    cout<<s;
    return 0;
}

if(i>n)break; 在循环里判

by jyb666 @ 2021-08-17 15:54:04

@谦上谦 有可能出现 i>n 却继续 s+=t

by vincent06 @ 2021-08-17 15:56:46

加完i的每一步都要判断i是否==n,否则会多加

by 谦上谦 @ 2021-08-18 20:46:01

感谢各位大神相助

本人已更改完毕并且正确，谢谢你们！

#include<bits/stdc++.h>
using namespace std;
int n,t=1,s;
int main()
{
    cin>>n;
    for (int i=1;i<=n;)
    {
        for (int j=1;j<=t;j++)
        {
            if(i>n)
                break;
            s+=t,i++;
        }
        t++;
        if(i>n)
            break;
    }
    cout<<s;
    return 0;
}