rabbitzph @ 2021-08-23 22:38:01
#include<iostream>
int m,n,cntm,cntn,cntr= 0;
using namespace std;
int main(){
int n = 0;
int sum = 0;
int res = 0;
int t1 = 0;
int t2 = 0;
int t3 = 0;
int temp = 0;
cin>>n;
for(int x = 1;x<=n;x++){//控制循环次数
cntm=0;
cntn=0;
cntr=0;
string str,str1;
cin>>str;
if(str[0]!=97&&str[0]!=98&&str[0]!=99){//判断是否输入了a,b,c ,若不是输入了a,b,c,强制使得这轮的运算符于上一轮相同
sum = 0;
for(int i = 0;i<str.size();i++){
if(i==0) temp = str.size();
for(int u =1;u<temp;u++){
str[i]*=10;
}
sum+=str[i];
}
m = sum;
cin>>n;
str = str1;
}
else{//若输入了a,b,c,正常输入后两个数字
str1 = str;
cin>>m>>n;
}
t1=m;
t2=n;
while(t1>0){//计算位数
t1/=10;cntm++;
}
while(t2>0){
t2/=10;cntn++;
}
if(str[0]=='a'){
t3 = res = m+n;
while(t3>0) t3/=10,cntr++;
cout<<m<<"+"<<n<<"="<<res<<endl;
cout<<cntr+cntm+cntn+2<<endl;
}
else if(str[0] =='b'){
t3 = res = m - n;
t3 = labs(t3);
while(t3>0) t3/=10,cntr++;
cout<<m<<"-"<<n<<"="<<res<<endl;
cout<<cntr+cntm+cntn+2<<endl;
}
else{
t3 = res = m * n ;
while(t3>0) t3/=10,cntr++;
cout<<m<<"*"<<n<<"="<<res<<endl<<cntr+cntm+cntn+2<<endl;
}
}
return 0 ;
}by 芝麻馅儿汤圆 @ 2021-08-24 00:05:40
#include <iostream>
#include <cstdio>
using namespace std;
int n;
string c;
char kind;
int num1, num2;
int ans;
int forbid;
void counting()
{
ans = 0;
if(num1 - num2 < 0 && kind == 'b')
ans++;
if(num1 == 0)
ans++;
if(num2 == 0)
ans++;
if(forbid == 0)
ans++;
while(num1)
{
ans++;
num1 /= 10;
}
while(num2)
{
ans++;
num2 /= 10;
}
while(forbid)
{
ans++;
forbid /= 10;
}
ans += 2;
}
void thoue()
{
if(kind == 'a')
{
cout << num1 << "+" << num2 << "=" << num1+num2 << endl;
forbid = num1+num2;
}
else if(kind == 'b')
{
cout << num1 << "-" << num2 << "=" << num1-num2 << endl;
forbid = num1-num2;
}
else
{
cout << num1 << "*" << num2 << "=" << num1*num2 << endl;
forbid = num1*num2;
}
}
int main()
{
cin >> n;
while(n--)
{
cin >> c;
num1 = 0;
num2 = 0;
ans = 0;
if(c[0] >= 'a' && c[0] <= 'c')
{
kind = c[0];
cin >> num1 >> num2;
thoue();
counting();
cout << ans << endl;
}
else
{
for(int k = 0; k < c.length(); k++)
{
num1 += c[k] - '0';
if(k != (c.length() - 1))
num1 = 10 * num1;
}
cin >> num2;
thoue();
counting();
cout << ans << endl;
}
}
return 0;
}