Demoe @ 2021-10-30 19:30:39
mxqz/kel
MLE ON #131
节点回收也写了 还是挂了/kk
// wish to get better qwq
#include<bits/stdc++.h>
#define re register int
#define pb push_back
#define lb lower_bound
#define ub upper_bound
#define mp make_pair
#define dec(x) fixed<<setprecision(x)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
template<class T> inline void rd(T &x){
int fl=1;x=0;char c=getchar();
for(;!isdigit(c);c=getchar()) if(c=='-') fl=-fl;
for(;isdigit(c);c=getchar()) x=(x<<3)+(x<<1)+c-'0';
x*=fl;
}
template<class T> inline void wr(T x){
if(x<0) x=-x,putchar('-');
if(x<10){putchar(x+'0');return ;}
int tmp[30]={0},cnt=0;
while(x) tmp[cnt++]=x%10,x/=10;
for(re i=cnt-1;i>=0;--i) putchar(tmp[i]+'0');
}
// ---------- IO ---------- //
const int N=1e6+5,M=1.919810e7+5;
int n,hd[N],tot,cnt,Ans[N];
struct edge{int nxt,t;}es[N<<1];
inline void add(int x,int y){es[++tot]=(edge){hd[x],y};hd[x]=tot;}
struct SGT{
#define mid ((l+r)>>1)
int rt[N],L[M],R[M],ans[M],id[M],st[M],tp=0;
inline int newnode(){if(tp) return st[tp--];return ++cnt;}
inline void del(int x){L[x]=R[x]=ans[x]=id[x]=0;st[++tp]=x;}
inline void pushup(int x){
if(ans[L[x]]>=ans[R[x]]) ans[x]=ans[L[x]],id[x]=id[L[x]];
else ans[x]=ans[R[x]],id[x]=id[R[x]];
}
inline int modify(int nw,int l,int r,int k){
if(!nw) nw=newnode();
if(l==r){++ans[nw];id[nw]=k;return nw;}
if(k<=mid) L[nw]=modify(L[nw],l,mid,k);
else R[nw]=modify(R[nw],mid+1,r,k);
pushup(nw);return nw;
}
inline int merge(int a,int b,int l,int r){
if(!a||!b) return (a|b);
if(l==r){ans[a]+=ans[b];id[a]=l;del(b);return a;}
L[a]=merge(L[a],L[b],l,mid),R[a]=merge(R[a],R[b],mid+1,r);
pushup(a);del(b);return a;
}
}T;
inline void dfs(int x,int fa,int dep){
for(re i=hd[x];i;i=es[i].nxt)
if(es[i].t!=fa) dfs(es[i].t,x,dep+1),T.rt[x]=T.merge(T.rt[x],T.rt[es[i].t],1,n);
T.rt[x]=T.modify(T.rt[x],1,n,dep);Ans[x]=T.id[T.rt[x]]-dep;
}
// ---------- ---------- //
int main(){
// freopen(".in","r",stdin);
// freopen(".out","w",stdout);
ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
cin>>n;
for(re i=1;i<n;++i){int u,v;cin>>u>>v;add(u,v);add(v,u);}
dfs(1,0,1);
for(re i=1;i<=n;++i) cout<<Ans[i]<<"\n";
return 0;
}
// ---------- Main ---------- //
by Saliеri @ 2021-10-30 19:34:16
@Demoe 推销:
by Demoe @ 2021-10-30 19:42:42
@Saliеri 已经改了为啥还 MLE 啊?
代码 link