yuhengtong222 @ 2016-08-17 10:14:49
var
n,i,x,k:longint;
a:array[1..1000000] of longint;
begin
for i:=1 to 10 do read(a[i]);
readln(n);
k:=30;
x:=0;
for i:=1 to 10 do;
if n+k>=a[i] then x:=x+1;
write(x);
end.
by GZOIxhx @ 2016-08-17 10:36:53
for i:=1 to 10 do 后面打了分号?
by GZOIxhx @ 2016-08-17 10:38:56
这样就只判断了第十个苹果能否摘到
by 20030103pz @ 2016-08-17 12:36:16
嗯
by syszs @ 2016-09-15 13:43:29
你这样做不对
by huzhaoyang @ 2016-09-16 08:42:45
嗯嗯嗯
把那个分号去掉
by Wh_Xcjm @ 2016-09-29 20:46:49
#include<iostream>
#include<iomanip>
#include<cstdlib>
#include<cmath>
using namespace std;
int main()
{
int i,j,s=0,a[11];
for(i=1;i<=10;i++)
cin>>a[i];
cin>>i;
for(j=1;j<=10;j++)
if(a[j]<=i+30)
s++;
cout<<s;
return 0;
}