80分求救

queshibuhui @ 2021-12-28 16:00:03

#include<stdio.h>
int main() {
    char c[14];
    scanf("%s", c);
    char a;
    int sum = 0;
    int j = 1;
    for (int i = 0; i < 12; i++) {
        if ((a = c[i]) == '-')continue;
        sum = sum + (a - '0') * j++;
    }
    sum = sum % 11;
    if (c[12] - '0' == sum)printf("Right");
    else {
        if (sum == 10)c[12] = 'X';
        else c[12] = sum + '0';
        printf("%s", c);
    }
}

by queshibuhui @ 2021-12-28 16:00:45

第四个过不去好奇怪

by dzn123456 @ 2021-12-28 16:54:42

哥，当最后一位为‘X'时，如果正确，sum%11==10,但c[12]-48=='X'-48!=10 改成这样

#include<cstdio>
#include<cstring>
#include<string>
#include<iostream>
#include<algorithm>
using namespace std;
int main()
{
    int b=0,a[10],sum=0;
    char s[20];
    for(int i=0;i<13;i++) cin>>s[i];
    for(int i=0;i<13;i++)
    {
        if(s[i]!='-')
        {
            if(s[i]!='X')
            a[b]=s[i]-48;
            else
            a[b]='X'-48;
            b++;
        }
    }
    for(int i=1;i<=9;i++) sum+=a[i-1]*i;
    if(sum%11==a[9]) cout<<"Right";
    else
    if(sum%11==10&&a[9]=='X'-48)
    cout<<"Right";
    else
    {
        for(int i=0;i<12;i++) cout<<s[i];
        if(sum%11==10) cout<<"X";
        else cout<<sum%11;
    }
}

iii，bye！~