一直70分跪求大佬帮一把

gpygy @ 2022-01-15 16:28:58

#include<stdio.h>
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
    int a,b,c,x;
    int i = 1;
    scanf("%d-%d-%d-%c",&a,&b,&c,&x);
    double a1 = a;double b1 = b;double c1 = c;
    b1 = b * 1.0 / 100;
    double sum1 = 0;
    for(i = 2;i <= 4;i++)
    {
        sum1 += (int)b1 % 10 * i;
        b1 = b1 * 10;
    }
    c1 = c * 1.0 / 10000;
    double sum2 = 0;
    for(i = 5;i <= 9;i++)
    {
        sum2 += (int)c1 % 10 * i;
        c1 = c1 * 10;
    }
    double sum = a + sum1 + sum2;

    double x1 = int(sum) % 11;
    if(x1 == 10 && x == 'X' || x1 == x - '0')
    {
        printf("Right");
    }
    else
    {
        char ch = x1 + 48;
        printf("%d-%d-%d-%c",a,b,c,x1 == 10?'X':ch);
    }
    return 0;   
}

by gpygy @ 2022-01-15 16:36:40

原来打错了一个x应该是字符类型的，刚才改了还是70分

by Mandel520 @ 2022-01-15 17:34:19

您好, 这是由于浮点数舍入误差导致的问题, 把b1和c1在求余运算前先加上0.1, 就可以AC了

修改后的程序如下:

#include<stdio.h>
#include<iostream>
#include<cmath>
using namespace std;

int main()
{
    int a,b,c,x;
    int i = 1;
    scanf("%d-%d-%d-%c",&a,&b,&c,&x);

    double a1 = a;double b1 = b;double c1 = c;
    b1 = b * 1.0 / 100;
    double sum1 = 0;
    for(i = 2;i <= 4;i++)
    {
        sum1 += (int)(b1 + 0.1) % 10 * i; //别忘了加0.1
        b1 = b1 * 10;
    }
    c1 = c * 1.0 / 10000;
    double sum2 = 0;
    for(i = 5;i <= 9;i++)
    {
        sum2 += (int)(c1 + 0.1) % 10 * i;//别忘了加0.1
        c1 = c1 * 10;
    }
    double sum = a + sum1 + sum2;

    double x1 = int(sum) % 11;
    if((x1 == 10 && x == 'X') || (x1 < 10 && x1 == x - '0'))
    {
        printf("Right\n");
    }
    else
    {
        char ch = x1 + 48;
        printf("%d-%d-%d-%c\n",a,b,c,x1 == 10?'X':ch);
    }
    return 0;   
}

by gpygy @ 2022-01-17 14:21:02

@Jeremy_Mandel 明白了，对了，感谢大佬的解答。