ytezlhy4372 @ 2022-02-03 21:39:39
用了两个void函数，只为main主函数里能简单点…… 求简化的代码如下：
#include<iostream>
#include<cstdio>
using namespace std;
int x,y,s1,s2;
void rn1(int a,int b){
for(int i=a;i<=b;i++){
if(i%4==0&&i%100!=0||i%400==0) s1++;
}
cout<<s1<<endl;
}
void rn2(int a,int b){
for(int j=a;j<=b;j++){
if(j%4==0&&j%100!=0||j%400==0) printf("%d ",j);
}
}
int main(){
cin>>x>>y;
rn1(x,y);
rn2(x,y);
return 0;
}by Escapism @ 2022-02-03 21:51:17
@lvhaoyang9 你可以用数组啊
by Escapism @ 2022-02-03 21:54:53
#include<iostream>
#include<cstdio>
using namespace std;
int x,y,s1,s2;
int year[10000];
void rn1(int a,int b){
for(int i=a;i<=b;i++){
if(i%4==0&&i%100!=0||i%400==0) {
s1++;
year[s1] = i;
}
}
cout<<s1<<endl;
for (int i = 1;i <= s1;i++) cout<<year[i]<<" ";
}
int main(){
cin>>x>>y;
rn1(x,y);
return 0;
}by 违规用户名ddc277a @ 2022-03-21 19:35:29
用数组干啥?
#include <bits/stdc++.h>
using namespace std;
int main() {
int x, y, sum=0;;
cin >> x >> y;
for (int i = x; i <= y; i ++ )
if(i % 400 == 0 || i % 4 == 0 && i % 100 != 0)
sum++;
cout << sum << endl;
for (int i = x; i <= y; i ++ )
if(i % 400 == 0 || i % 4 == 0 && i % 100 != 0)
cout << i << " ";
cout << endl;
return 0;
}