30分求调

P5707 【深基2.例12】上学迟到

@[Maysoul](/user/409774) ```c++ #include <iostream> #include <math.h> using namespace std; int main() { double s, v; cin >> s >> v; int t = ceil(s/v) + 10; //求走过去的时间,ceil()是向上取整 int h = t / 60; //求小时数 int m = t % 60; //求分钟数 if (h < 8)//走过去不到8小时 { if (m == 0) { h = 8 - h; //出发的小时数=8:00-h m = 0; } else { h = 7 - h; //出发的小时数=7:00-h m = 60 - m; //出发的分钟数 } } else { h -= 8; //时间大于8小时,减去8 if (h == 0) { if (m != 0) { h = 23; m = 60 - m; } } else { h = 24 - h; if (m != 0) { h -= 1; m = 60 - m; } } } if (h < 10) //补0 { if (m < 10) //补0 cout << "0" << h << ":" << "0" << m; else cout << "0" << h << ":" << m; } else { if (m < 10) //补0 cout << h << ":" << "0" << m; else cout << h << ":" << m; } return 0; } ```
by Jasper08 @ 2022-03-17 09:16:23


话说您都会 BFS 了怎么不会这个(
by Jasper08 @ 2022-03-17 09:21:38


@[Jasper08](/user/581830) ~~因为懒得自己查错~~
by Maysoul @ 2022-03-17 10:01:04


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