gpygy @ 2022-03-23 08:23:50
#include<iostream>
using namespace std;
int main()
{
int n;
cin>>n;
n = n % 26;
string a;
cin.get();
getline(cin,a);
for(int i = 0;i < a.length();i++)
{
int j = 'z' - a[i];
if(j >= n)
{
a[i] = a[i] + n;
}
else
{
a[i] = 'a' + n - j - 1;
}
}
cout<<a;
return 0;
}
by Jerrlee✅ @ 2022-03-23 08:30:33
@gpygy https://www.luogu.com.cn/record/72116091
两端 getline
即可通过,大概是第一次读入时读入了 \n
。
by rxjdasiwzl @ 2022-03-23 09:24:59
@gpygy 混用 std::cin >> n
和 std::getline
by gpygy @ 2022-03-23 09:34:33
@Jerrlee✅ 好的,谢谢