xixi_coding @ 2022-04-15 22:48:42
import math
t = int(input())
if t == 1:
print('I love Luogu!')
elif t == 2:
print(2 + 4, 10 - 2 - 4)
elif t == 3:
a = 14 // 4
print(a)
print(a * 4)
print(14 % 4)
elif t == 4:
print(round(500 / 3, 3))
elif t == 5:
print((260 + 220)//(12+20))
elif t == 6:
def cout():
print(math.sqrt(36 + 81))
cout()
elif t == 7:
money = 100
money = money + 10
print(money)
money = money - 20
print(money)
print(0)
elif t == 8:
r = 5
a = 3.141593
print(a * r*2)
print(a * r**2)
print(4/3 * a * r**3)
elif t == 9:
x = 1
for i in range(3):
x = (x + 1) * 2
print(x)
elif t == 10:
y = (8 * 30 - 10 * 6)/(30 - 6)
x = 8 * 30 - 30 * y
z = int((x + 10 * y) / 10)
print(z)
elif t == 11:
print(100/(8-5))
elif t == 12:
print(ord('M') - ord('A') + 1)
print(chr(ord('A') + 18 - 1))
elif t == 13:
pi = 3.141593
print(int((4/3 * pi * 4 ** 3 + 4/3 * pi * 10 ** 3)**(1/3)))
elif t == 14:
price = 110
n = 10
a = 0
b = 0
while price > 0:
price -= 1
n += 1
if n * price == 3500:
a = price
b = n
print(a)
by Missa @ 2022-04-15 22:52:37
这里的 cout
指的是 c++ 中的 cout
,你的 python
估计被卡小数位数了。
by Terrible @ 2022-04-15 22:56:51
@fqx_218
cout
默认6位有效数字,Python的C格式化输出:print("%.6g"%f)
by xixi_coding @ 2022-04-15 23:14:57
@Terrible 我去试一下
by 176lhp @ 2022-06-16 10:52:34
@Terrible 保留6位有效数字和保留6位小数一样吗?
by Terrible @ 2022-06-16 12:26:50
@176lhp 不一样,保留6位有效数字是从第一个非零数字开始算6位,保留6位小数是从小数点后算6位。
比如
by BG5CNR @ 2023-05-01 18:18:50
@fqx_218 请问,14题用枚举的话,怎么取到小的值?用枚举是两个值都会输出的。