1214__qwq @ 2022-04-19 09:38:26
#include <iostream>
using namespace std;
int n, a[105][10], count = 0;
char c;
int main()
{
cin >> n;
for(int i = 1; i <= n; i++)
{
for(int j = 1; j <= 4; j++)
{
c = getchar();
a[i][j] = (int)(c - 48);
}
getchar();
if(a[i][4] - a[i][1] - a[i][2] - a[i][3] > 0)
count++;
}
cout << count << endl;
return 0;
}
用字符读每一位存进二维数组里面,为啥不对
by 1214__qwq @ 2022-04-19 09:39:55
本地测试样例也不行,输出是5
by FQR_ @ 2022-04-19 09:53:56
@ryng1214 八成是读入出了问题,直接用string的cin吧。
by WilliamFranklin @ 2022-04-19 09:56:54
#include <iostream>
using namespace std;
int n, a[105][10], count = 0;
char c;
int main()
{
cin >> n;
getchar();
for(int i = 1; i <= n; i++)
{
for(int j = 1; j <= 4; j++)
{
cin>>c;
a[i][j] = (c - 48);
}
getchar();
if(a[i][4] - a[i][1] - a[i][2] - a[i][3] > 0)
count++;
}
cout << count << endl;
return 0;
}
在你基础上改了一下(尽量用cin
by 编码落寞 @ 2022-04-19 09:58:02
@ryng1214
环境不一样,第二个地方
getchar();
getchar();
放两个,是可以过样例的
by 1214__qwq @ 2022-04-19 10:04:17
@WilliamFranklin 过了,谢谢
by 2024yejinghong @ 2023-08-22 17:54:14
#include<bits/stdc++.h>
using namespace std;
int main()
{
int n,ans=0;
cin>>n;
for(int i=1;i<=n;i++)
{
int m,a,b,c,d;
cin>>m;
a=m%10;
b=m/10%10;
c=m/100%10;
d=m/1000;
if(a-b-c-d>0)
{
ans++;
}
}
cout<<ans;
return 0;
}