xiaobaiwww @ 2022-05-15 22:25:20
n = int(input())
sum = 0
ls = []
for i in range(1,n+1):
for j in range (1,i+1):
ls.append(i)
for k in range(n):
sum = sum + ls[k]
print(sum)
by xiaobaiwww @ 2022-05-15 22:29:34
思路就是先输出所有的数字到列表 只要将输入的数字根据列表中循环加上输出就可以 但是时间优化上可能不是很好 超过一万的时候时间在1.4秒左右
by Xeqwq @ 2022-05-15 22:57:45
@xiaobaiwww 本地输出 打表
by liusanrong @ 2022-06-09 10:54:57
k = int(input())
a = 1
i = 1
while a <= k:
a += i
i += 1
sum_v = 0
for j in range(1, i-1):
sum_v += j*j
sum_v += (k-(a-(i-1))+1)*(i-1)
print(sum_v)
by __mcr130102__ @ 2022-12-22 19:06:37
k = int(input())
a = 1
i = 1
while a <= k:
a += i
i += 1
sum_v = 0
for j in range(1, i-1):
sum_v += j*j
sum_v += (k-(a-(i-1))+1)*(i-1)
print(sum_v)