这个题解26~31什么意思

#include<iostream>
#include<algorithm>
using namespace std;
string yw[30]={"","one","two","three","four","five","six","seven",
"eight","nine","ten","elven","twelve","thirteen","fourteen","fifteen",
"sixteen","seventeen","eighteen","nineteen","twenty","a","both",
"another","first","second","third"}; 
int sz[30]={0,1,4,9,16,25,36,49,64,81,0,21,44,69,96,25,56,89,24,61,0,
1,4,1,1,4,9};
int k;
int a[10];

int main()
{
    for(int i=1;i<=6;i++)
    {
        string x;
        cin>>x;//直接用变量读就行了
        for(int j=1;j<=26;j++)//26种英文数字
            if(yw[j]==x)
                {a[++k]=sz[j];break;}//k记录有几个英文数字
    }
    if(k==0){cout<<0<<endl;return 0;}//先判断一下句子中有没有英文数字
    sort(a+1,a+k+1);//排序//26
    for(int i=1;i<=k;i++)
    {
        if(i!=1&&a[i]<10)cout<<0;//补0
        cout<<a[i];
    }//31
    cout<<endl;
    return 0;
}